Tutor: Hi! I am now working on your question and you will soon see me writing on your drawing board.
Tutor: Hello :)
Student: Hi
Student: Just looking for answer
Tutor: OK...just a minute..
Tutor: There would be no X-intercepts
Student: Ok
Tutor: Y-intercept = 16
Tutor: Should I solve it for you?
Student: No that is good
Student: Can i ask another
Tutor: Ya sure :)
Student: Mark the statement as true or false.
The absolute value of any nonzero number is positive
Tutor: True
Student: Cool
Student: Can i ask another
Student: Find the value of the expression.
log3 81
Tutor: Yes... :)
Student: Ok
Tutor: The answer is 4
Student: Ok
Student: Solve the equation.
=
Tutor: Sorry can't see the equation...please write it on the board...
Student: |4s+7|=|s+9|
Tutor: Square both the sides...
Student: So no solution?
Tutor: You want the answer only?
Student: Yes]
Student: Just checking homework
Tutor: OK...
Tutor: Wait...
Tutor: Ther would be two solutions...
Student: Ok
Tutor: -16/5
and
2/3
Student: Cool
Student: Give the equation of the horizontal asymptote of the rational function
Student: (g)x=5/9x+5
Student: I got X= -5/9
Tutor: Did I write the function correctly?
Student: I cant see it
Student: I think my board isnt working
Student: Ok now i see it
Tutor: Is this right?
Student: Yes
Tutor: The answer would be:: Y=5
Tutor: See here we need to find the horizontal asymptote...
Student: Ok
Student: Find the sum of the first five terms of the geometric sequence
Tutor: Which means that the value of y for which X becomes infinite...
Student: A=3/2 , r=2
Tutor: Should i solve the previous question and show ou how i got Y=5
Student: No
Tutor: OK.. :)
Student: So
Student: Find the sum of the first five terms of the geometric sequence
Tutor: Please write the geometric sequence...
Student: A=3/2 r=2
Student: Is that ok
Tutor: The question...yeah...A is the first term of the sequence and Ris the common ratio for the terms...
Student: Ok
Student: I got 93
Tutor: Answer is 93/2
Student: Find the value of the expression.
log8 1/512
Student: Yes
Tutor: Answer is (-3)
Student: Determine whether the given ordered pair is a solution of the given equation.
(x - 5)2 + (y + 7)2 = -16; (2, -2)
Tutor: No...
Student: No
Student: ?
Tutor: The ordered pair is not a solution...
Student: Write in logarithmic form.
e^-2 = 0.1353
Tutor: Is this correct?
Student: Yes
Tutor: Applying natural log on both sides...
Student: Ok
Tutor: This is the answer...
Tutor: :)
Student: Ok
Student: Simplify the expression. Write answer with positive exponents.
Student: 6^-7/6^5
Tutor: Is this the question?
Student: No
Tutor: Is this correct?
Student: 6^-7 over 6^5
Tutor: OK :)
Tutor: This is the answer with positive exponents...
Tutor: :)
Student: Ok
Tutor: Are there any more questions that I can help you with?
Student: Yes
Student: Write the expression as the logarithm of a single number or expression with a coefficient of 1. Assume all variables represent positive numbers.
log 30 - log 6
Student: Ok
Tutor: This is the answer :)
Student: Cool
Student: Solve the inequality and graph the solution.
v2 - 6v + 8 ≥ 0
Student: So its 2 and 4
Tutor: This would be the answer.. :)
Tutor: No...
Tutor: Since this is ans inequality
Tutor: So the answer would also be an inequality
Tutor: The answer would be...
Tutor: V > 4 || V < 2
Student: Ok
Student:
28.
Find the range for the set of data numbers
Student: 116,502,150,566,427,243
Student: I got 450
Tutor: Wait a minute :)
Tutor: Range would be 566 - 116 = 450
Tutor: You are right!! :)
Student: Ok cool
Student: Solve the equation for s.
ln (r + 4) = ln (5s + 2)
Student: I got 5 / r +2
Tutor: This would be the asnwer :)
Student: Ok cool
Student: Factor completely.
x2 + 3xy - 108y2
Student: I got prime
Tutor: This would be the answer... :)
Student: Cool
Student: Find the number of subsets of the set.
{1, 2, 3, . . . , 9}
Student: I got 508
Tutor: The number of subsets = 2^N
Tutor: Where N is the number of elements in the set
Student: Ok
Student: So 16?
Tutor: Here N=9
Student: Ok
Student: Cool
Student: Graph the linear function.
g(x) = x - 5
Tutor: This would be the answer :)
Student: Ok
Tutor: For X=0 , g(X) = -5
Student: Ok
Tutor: For g(X)=0 , X=5
Tutor: Now we'll make a line passing through these two points... :)
Student: Ok
Student: Cook
Student: Factor completely.
x2 - x - 42
Tutor: This is the answer :)
Student: Ok
Student: Graph the linear inequality.
x - y < 3
Tutor: Do you know how we split the middle term?
Student: ?
Student: Ok
Student: I got
Tutor: I was asking about the previous question....why i plit -X = -7X + 6X
Student: Ok
Student: Yes
Tutor: Correct!!
Tutor: The intercepts would be 3
Student: Graph the polynomial function.
f(x) = x3 - 4x - 1
Student: Ok
Tutor: Is it x^3 or x^2?
Student: Student has ended this session. This question is automatically marked as done.
Student: 3
Tutor: OK...
Student: I got
Tutor: At what value of X, Y would be zero?
Student: I got something like that
Tutor: Yeah...it would be something like that only..
Student: Ok
Tutor: Your session has ended...I think you need to recharge your minutes...please ask the question again... :)
Tutor: I mean send the question as a fresh one...
Tutor: OK?
Student: Ok
Tutor: Hello :)
Student: Hi
Student: Just looking for answer
Tutor: OK...just a minute..
Tutor: There would be no X-intercepts
Student: Ok
Tutor: Y-intercept = 16
Tutor: Should I solve it for you?
Student: No that is good
Student: Can i ask another
Tutor: Ya sure :)
Student: Mark the statement as true or false.
The absolute value of any nonzero number is positive
Tutor: True
Student: Cool
Student: Can i ask another
Student: Find the value of the expression.
log3 81
Tutor: Yes... :)
Student: Ok
Tutor: The answer is 4
Student: Ok
Student: Solve the equation.
=
Tutor: Sorry can't see the equation...please write it on the board...
Student: |4s+7|=|s+9|
Tutor: Square both the sides...
Student: So no solution?
Tutor: You want the answer only?
Student: Yes]
Student: Just checking homework
Tutor: OK...
Tutor: Wait...
Tutor: Ther would be two solutions...
Student: Ok
Tutor: -16/5
and
2/3
Student: Cool
Student: Give the equation of the horizontal asymptote of the rational function
Student: (g)x=5/9x+5
Student: I got X= -5/9
Tutor: Did I write the function correctly?
Student: I cant see it
Student: I think my board isnt working
Student: Ok now i see it
Tutor: Is this right?
Student: Yes
Tutor: The answer would be:: Y=5
Tutor: See here we need to find the horizontal asymptote...
Student: Ok
Student: Find the sum of the first five terms of the geometric sequence
Tutor: Which means that the value of y for which X becomes infinite...
Student: A=3/2 , r=2
Tutor: Should i solve the previous question and show ou how i got Y=5
Student: No
Tutor: OK.. :)
Student: So
Student: Find the sum of the first five terms of the geometric sequence
Tutor: Please write the geometric sequence...
Student: A=3/2 r=2
Student: Is that ok
Tutor: The question...yeah...A is the first term of the sequence and Ris the common ratio for the terms...
Student: Ok
Student: I got 93
Tutor: Answer is 93/2
Student: Find the value of the expression.
log8 1/512
Student: Yes
Tutor: Answer is (-3)
Student: Determine whether the given ordered pair is a solution of the given equation.
(x - 5)2 + (y + 7)2 = -16; (2, -2)
Tutor: No...
Student: No
Student: ?
Tutor: The ordered pair is not a solution...
Student: Write in logarithmic form.
e^-2 = 0.1353
Tutor: Is this correct?
Student: Yes
Tutor: Applying natural log on both sides...
Student: Ok
Tutor: This is the answer...
Tutor: :)
Student: Ok
Student: Simplify the expression. Write answer with positive exponents.
Student: 6^-7/6^5
Tutor: Is this the question?
Student: No
Tutor: Is this correct?
Student: 6^-7 over 6^5
Tutor: OK :)
Tutor: This is the answer with positive exponents...
Tutor: :)
Student: Ok
Tutor: Are there any more questions that I can help you with?
Student: Yes
Student: Write the expression as the logarithm of a single number or expression with a coefficient of 1. Assume all variables represent positive numbers.
log 30 - log 6
Student: Ok
Tutor: This is the answer :)
Student: Cool
Student: Solve the inequality and graph the solution.
v2 - 6v + 8 ≥ 0
Student: So its 2 and 4
Tutor: This would be the answer.. :)
Tutor: No...
Tutor: Since this is ans inequality
Tutor: So the answer would also be an inequality
Tutor: The answer would be...
Tutor: V > 4 || V < 2
Student: Ok
Student:
28.
Find the range for the set of data numbers
Student: 116,502,150,566,427,243
Student: I got 450
Tutor: Wait a minute :)
Tutor: Range would be 566 - 116 = 450
Tutor: You are right!! :)
Student: Ok cool
Student: Solve the equation for s.
ln (r + 4) = ln (5s + 2)
Student: I got 5 / r +2
Tutor: This would be the asnwer :)
Student: Ok cool
Student: Factor completely.
x2 + 3xy - 108y2
Student: I got prime
Tutor: This would be the answer... :)
Student: Cool
Student: Find the number of subsets of the set.
{1, 2, 3, . . . , 9}
Student: I got 508
Tutor: The number of subsets = 2^N
Tutor: Where N is the number of elements in the set
Student: Ok
Student: So 16?
Tutor: Here N=9
Student: Ok
Student: Cool
Student: Graph the linear function.
g(x) = x - 5
Tutor: This would be the answer :)
Student: Ok
Tutor: For X=0 , g(X) = -5
Student: Ok
Tutor: For g(X)=0 , X=5
Tutor: Now we'll make a line passing through these two points... :)
Student: Ok
Student: Cook
Student: Factor completely.
x2 - x - 42
Tutor: This is the answer :)
Student: Ok
Student: Graph the linear inequality.
x - y < 3
Tutor: Do you know how we split the middle term?
Student: ?
Student: Ok
Student: I got
Tutor: I was asking about the previous question....why i plit -X = -7X + 6X
Student: Ok
Student: Yes
Tutor: Correct!!
Tutor: The intercepts would be 3
Student: Graph the polynomial function.
f(x) = x3 - 4x - 1
Student: Ok
Tutor: Is it x^3 or x^2?
Student: Student has ended this session. This question is automatically marked as done.
Student: 3
Tutor: OK...
Student: I got
Tutor: At what value of X, Y would be zero?
Student: I got something like that
Tutor: Yeah...it would be something like that only..
Student: Ok
Tutor: Your session has ended...I think you need to recharge your minutes...please ask the question again... :)
Tutor: I mean send the question as a fresh one...
Tutor: OK?
Student: Ok