Tutor: Hi! I am now working on your question and you will soon see me writing on your drawing board.
Tutor: Hello
Student: Hello there
Tutor: Any questions so far?
Student: No not so far
Tutor: Now what is the value of (-3)^3 ?
Student: -27
Tutor: Correct
Tutor: And what is the value of 2(-3)^2 ?
Student: 18
Tutor: What is the value of - 27 - 18 - 9 ?
Student: -54
Tutor: Correct
Tutor: That is the answer
Tutor: I hope I have been clear
Student: You have been I got the sign wrong
Student: I have a quizz I have to go over for monday can you help me ckeck some more answers
Tutor: Yes
Student: Which of the following functions has exactly 1 distinct real zero? A) f(x) = x6 - 1
B) g(x) = x3 - x2 + x - 1
C) h(x) = x3 - 2x2 - x + 2
D) p(x) = x4 - 3x2 + 2
E) p(x) = x4 + 3x2 + 2
F) none of these
Tutor: Am I being clear so far?
Tutor: The answer will be B
Tutor: But we need to check all
Student: Are you factoring these?
Tutor: Yes
Student: OK
Tutor: And each linear factor gives one real solution
Tutor: We see that
Tutor: A has 2 solutions
Tutor: B has 1 solution
Tutor: C has 3
Tutor: D has 4
Tutor: And E has none
Tutor: So the correct answer is B
Student: Can you explain E please
Student: The way you set these up on the screen are very helpful thankyou
Student: How many asymptotes are there for the graph of
y = x3/[(x2 - 1)(x2 - 2)(x + 1)] ?
Student: Is that clear
Tutor: Ok
Tutor: Let me see
Tutor: So the two asymptotes are
Tutor: Sory
Tutor: The asymptotes are
Tutor: Four
Tutor: X = 1
Tutor: X = -1
Tutor: X = sqrt(2)
Tutor: X = - sqrt(2)
Student: So I have three?
Student: Why not the -1
Student: Oops
Student: So there are 4
Student: Right
Tutor: Yes
Tutor: Total four asymptotes
Student: So if there is a repeat than it is only counted as One?
Tutor: Yes
Student: Ok got it
Tutor: We have repeat at -1
Tutor: Great :)
Student: the next one seems easy but I was wrong
Student: Solve: (x + 1)/(x - 2) < 3
Tutor: Any questions so far?
Student: I dont think so
Tutor: The roots of (-2x + 7)(x -2 ) are
Tutor: X = 7/2 and x = 2
Tutor: So the product is less than 0,
Tutor: When it lies in between 2 and 7/2]
Student: X < 2 or x > 7/2
Student: Or
Student: 2 < x < 7/2
Student: I cant interperit this
Tutor: That is the answer
Student: Ok hang on while i go over it please
Tutor: Ok
Student: Ok got it
Student: The next one confuses me I can do synthetic division but not in this format
Student: Use synthetic division to find the quotient and remainder. Match your result to the correct answer below.
(x2 + 6x + 4) ÷ (x + 3)
Student: A) x + 9, R = 31
B) x + 3, R = –5
C) x – 9, R = 31
D) x – 3, R = –5
Student: So how does it get set up
Tutor: When we have x + 3, we take it as -3
Tutor: Any questions so far?
Student: I think i get already
Tutor: Ok
Tutor: So B is the answer
Student: Great I just couldnt figure how to get from the equation to syn division format
Tutor: Ok
Tutor: Are there any more questions that I can help you with?
Student: Perfect
Student: yes I have quit a few more is that OK?
Student: Opps
Student: Quite afew
Tutor: Yes
Tutor: Sure
Student: Use the Upper and Lower Bound Thm to find the smallest positive integer multiple of 10 and the largest negative integer multiple of 10 that are upper and lower bounds, respectively for the real zeros of P(x) = x3 – 100x2 + 12.
Student: A) 20 and -100
B) 10 and -100
C) 100 and –20
D) 100 and –10
Student: I just dont get this AT ALL
Tutor: Let me work on it
Tutor: Can we move ahead to next one, while I think on this one
Student: Yes
Student: What is the remainder when x3 + 19x2 + 114x + 219 is divided by (x + 4)? A) 4
B) 6
C) 9
D) 3
Tutor: Ok
Student: Are you still there?
Tutor: Yes
Student: Sorry
Tutor: Working onyour quesiton
Student: OK sorry
Tutor: That ist he answer
Tutor: I hope I have been clear
Student: I dont see anything on the screen
Tutor: Please refresh
Student: Just did thatks
Student: For P(x) = x3 – ix2 + x – i find P(–1 + i).
Student: A) 1 + 2i
B) 1 – 2i
C) – 1 + 2i
D) 2 + i
Student: I is imaginary number right
Tutor: Yes
Student: Ok
Tutor: So now we found these two
Tutor: We shall use it in our question
Tutor: Any questions so far?
Student: No I am with you
Tutor: Wait, we can do it in other way
Tutor: Ok
Tutor: So that ist he asnwr
Tutor: I hope I have been clear
Student: OK let me look it over
Student: OK
Student: Next one
Student: 2x + 1 is a factor of 10x3 - 17x2 - 7x + 2 A) True
B) False
Tutor: As P(-1/2) = 0, 2x + 1 is a factor
Student: True then
Tutor: So the answer is TRUe]
Student: Right?
Tutor: Yes
Student: Find b so that x - 1 is a factor of x 5 + x 4 + x 2 + b.
Student: A) -3
B) -4
C) -5
D) -6
E) none of these
Student: Is this syn division again
Tutor: No
Tutor: As we are given that
Tutor: X - 1 is afactor
Tutor: We take P(1) = 0
Tutor: That is the answer
Tutor: I hope I hav ebeen clear
Student: B=0
Student: Is that right
Tutor: B = -3
Student: I got it
Student: I still have more to go over I hope I am not taking to much of your time
Tutor: No not at all
Tutor: Please give your next question
Student: Great:)
Student: A real solution for the equation x3 + 2x2 - 11x - 22 = 0, correct to the nearest tenth, is
x =
Student: A) -0.7
B) 0.5
C) 0.7
D) 1.2
E) 3.3
F) none of these
Student: Student has ended this session. This question is automatically marked as done.
Tutor: The answer to your quesiton is thsere on the bord
Tutor: The session has been ended
Tutor: So please if you have more questions then give it as new question in a new window :)
Tutor: I need to close the window now
Student: Ok
Tutor: Good bye. Thank you for using Instant Math Help.
Tutor: Hello
Student: Hello there
Tutor: Any questions so far?
Student: No not so far
Tutor: Now what is the value of (-3)^3 ?
Student: -27
Tutor: Correct
Tutor: And what is the value of 2(-3)^2 ?
Student: 18
Tutor: What is the value of - 27 - 18 - 9 ?
Student: -54
Tutor: Correct
Tutor: That is the answer
Tutor: I hope I have been clear
Student: You have been I got the sign wrong
Student: I have a quizz I have to go over for monday can you help me ckeck some more answers
Tutor: Yes
Student: Which of the following functions has exactly 1 distinct real zero? A) f(x) = x6 - 1
B) g(x) = x3 - x2 + x - 1
C) h(x) = x3 - 2x2 - x + 2
D) p(x) = x4 - 3x2 + 2
E) p(x) = x4 + 3x2 + 2
F) none of these
Tutor: Am I being clear so far?
Tutor: The answer will be B
Tutor: But we need to check all
Student: Are you factoring these?
Tutor: Yes
Student: OK
Tutor: And each linear factor gives one real solution
Tutor: We see that
Tutor: A has 2 solutions
Tutor: B has 1 solution
Tutor: C has 3
Tutor: D has 4
Tutor: And E has none
Tutor: So the correct answer is B
Student: Can you explain E please
Student: The way you set these up on the screen are very helpful thankyou
Student: How many asymptotes are there for the graph of
y = x3/[(x2 - 1)(x2 - 2)(x + 1)] ?
Student: Is that clear
Tutor: Ok
Tutor: Let me see
Tutor: So the two asymptotes are
Tutor: Sory
Tutor: The asymptotes are
Tutor: Four
Tutor: X = 1
Tutor: X = -1
Tutor: X = sqrt(2)
Tutor: X = - sqrt(2)
Student: So I have three?
Student: Why not the -1
Student: Oops
Student: So there are 4
Student: Right
Tutor: Yes
Tutor: Total four asymptotes
Student: So if there is a repeat than it is only counted as One?
Tutor: Yes
Student: Ok got it
Tutor: We have repeat at -1
Tutor: Great :)
Student: the next one seems easy but I was wrong
Student: Solve: (x + 1)/(x - 2) < 3
Tutor: Any questions so far?
Student: I dont think so
Tutor: The roots of (-2x + 7)(x -2 ) are
Tutor: X = 7/2 and x = 2
Tutor: So the product is less than 0,
Tutor: When it lies in between 2 and 7/2]
Student: X < 2 or x > 7/2
Student: Or
Student: 2 < x < 7/2
Student: I cant interperit this
Tutor: That is the answer
Student: Ok hang on while i go over it please
Tutor: Ok
Student: Ok got it
Student: The next one confuses me I can do synthetic division but not in this format
Student: Use synthetic division to find the quotient and remainder. Match your result to the correct answer below.
(x2 + 6x + 4) ÷ (x + 3)
Student: A) x + 9, R = 31
B) x + 3, R = –5
C) x – 9, R = 31
D) x – 3, R = –5
Student: So how does it get set up
Tutor: When we have x + 3, we take it as -3
Tutor: Any questions so far?
Student: I think i get already
Tutor: Ok
Tutor: So B is the answer
Student: Great I just couldnt figure how to get from the equation to syn division format
Tutor: Ok
Tutor: Are there any more questions that I can help you with?
Student: Perfect
Student: yes I have quit a few more is that OK?
Student: Opps
Student: Quite afew
Tutor: Yes
Tutor: Sure
Student: Use the Upper and Lower Bound Thm to find the smallest positive integer multiple of 10 and the largest negative integer multiple of 10 that are upper and lower bounds, respectively for the real zeros of P(x) = x3 – 100x2 + 12.
Student: A) 20 and -100
B) 10 and -100
C) 100 and –20
D) 100 and –10
Student: I just dont get this AT ALL
Tutor: Let me work on it
Tutor: Can we move ahead to next one, while I think on this one
Student: Yes
Student: What is the remainder when x3 + 19x2 + 114x + 219 is divided by (x + 4)? A) 4
B) 6
C) 9
D) 3
Tutor: Ok
Student: Are you still there?
Tutor: Yes
Student: Sorry
Tutor: Working onyour quesiton
Student: OK sorry
Tutor: That ist he answer
Tutor: I hope I have been clear
Student: I dont see anything on the screen
Tutor: Please refresh
Student: Just did thatks
Student: For P(x) = x3 – ix2 + x – i find P(–1 + i).
Student: A) 1 + 2i
B) 1 – 2i
C) – 1 + 2i
D) 2 + i
Student: I is imaginary number right
Tutor: Yes
Student: Ok
Tutor: So now we found these two
Tutor: We shall use it in our question
Tutor: Any questions so far?
Student: No I am with you
Tutor: Wait, we can do it in other way
Tutor: Ok
Tutor: So that ist he asnwr
Tutor: I hope I have been clear
Student: OK let me look it over
Student: OK
Student: Next one
Student: 2x + 1 is a factor of 10x3 - 17x2 - 7x + 2 A) True
B) False
Tutor: As P(-1/2) = 0, 2x + 1 is a factor
Student: True then
Tutor: So the answer is TRUe]
Student: Right?
Tutor: Yes
Student: Find b so that x - 1 is a factor of x 5 + x 4 + x 2 + b.
Student: A) -3
B) -4
C) -5
D) -6
E) none of these
Student: Is this syn division again
Tutor: No
Tutor: As we are given that
Tutor: X - 1 is afactor
Tutor: We take P(1) = 0
Tutor: That is the answer
Tutor: I hope I hav ebeen clear
Student: B=0
Student: Is that right
Tutor: B = -3
Student: I got it
Student: I still have more to go over I hope I am not taking to much of your time
Tutor: No not at all
Tutor: Please give your next question
Student: Great:)
Student: A real solution for the equation x3 + 2x2 - 11x - 22 = 0, correct to the nearest tenth, is
x =
Student: A) -0.7
B) 0.5
C) 0.7
D) 1.2
E) 3.3
F) none of these
Student: Student has ended this session. This question is automatically marked as done.
Tutor: The answer to your quesiton is thsere on the bord
Tutor: The session has been ended
Tutor: So please if you have more questions then give it as new question in a new window :)
Tutor: I need to close the window now
Student: Ok
Tutor: Good bye. Thank you for using Instant Math Help.